C# program to Find Worker efficiency using if_else statement

C# program to find Worker efficiency using if_else statement
Program statement:In a company, worker efficiency is determined on the basis of the time required for a worker to complete a particular job. If the time taken by the worker is between 2 – 3 hours, then the worker is said to be highly efficient. If the time required by the worker is between 3 – 4 hours, then the worker is ordered to improve speed. If the time taken is between 4 – 5 hours, the worker is given training to improve his speed, and if the time taken by the worker is more than 5 hours, then the worker has to lve the company. If the time taken by the worker is input through the board, find the efficiency of the worker.
Solution:static void Main(string[] args)
{
double time;
Console.WriteLine("Enter the Worker's Time to complete Task:");
time = Convert.ToDouble(Console.RdLine());
if (time >= 2 && time <=3)
Console.WriteLine("Good! Worked Efficiently");
else if(time>3 && time<=4)
Console.WriteLine("Improved Your working Speed");
else if(time>4 && time<=5)
Console.WriteLine("Required Tranning to improve Speed");
else if(time>5)
Console.WriteLine("Lve this company");
else
Console.WriteLine("No Result for this input");
Console.RdLine();
}